Uniformity trial of barley at Cambridge, England, 1978.

Details

A uniformity trial of spring barley planted in 1978. Conducted by the Plant Breeding Institute in Cambridge, England.

Each plot is 5 feet wide, 14 feet long.

Field width: 7 plots * 14 feet = 98 feet

Field length: 28 plots * 5 feet = 140 feet

Format

A data frame with 196 observations on the following 3 variables.

row

row

col

column

yield

grain yield, kg

Source

R. A. Kempton and C. W. Howes (1981). The use of neighbouring plot values in the analysis of variety trials. Applied Statistics, 30, 59--70. https://doi.org/10.2307/2346657

References

McCullagh, P. and Clifford, D., (2006). Evidence for conformal invariance of crop yields, Proceedings of the Royal Society A: Mathematical, Physical and Engineering Science. 462, 2119--2143. https://doi.org/10.1098/rspa.2006.1667

Examples

# \dontrun{ library(agridat) data(kempton.barley.uniformity) dat <- kempton.barley.uniformity libs(desplot) desplot(dat, yield~col*row, aspect=140/98, tick=TRUE, # true aspect main="kempton.barley.uniformity")
# Kempton estimated auto-regression coefficients b1=0.10, b2=0.91 dat <- transform(dat, xf = factor(col), yf=factor(row)) # ---------- libs(asreml,lucid) # asreml4 dat <- transform(dat, xf = factor(col), yf=factor(row)) m1 <- asreml(yield ~ 1, data=dat, resid = ~ar1(xf):ar1(yf))
#> Model fitted using the gamma parameterization. #> ASReml 4.1.0 Mon Jan 11 17:08:48 2021 #> LogLik Sigma2 DF wall cpu #> 1 138.768 0.0880303 195 17:08:48 0.0 (1 restrained) #> 2 190.210 0.0624855 195 17:08:48 0.0 #> 3 224.660 0.0667102 195 17:08:48 0.0 #> 4 230.382 0.0828740 195 17:08:48 0.0 #> 5 231.397 0.0999127 195 17:08:48 0.0 #> 6 231.425 0.1038940 195 17:08:48 0.0 #> 7 231.425 0.1043644 195 17:08:48 0.0
# vc(m1) ## effect component std.error z.ratio bound ## xf:yf!R 0.1044 0.02197 4.7 P 0 ## xf:yf!xf!cor 0.2458 0.07484 3.3 U 0 ## xf:yf!yf!cor 0.8186 0.03821 21 U 0 # asreml estimates auto-regression correlations of 0.25, 0.82 # Kempton estimated auto-regression coefficients b1=0.10, b2=0.91 # ---------- if(0){ # Kempton defines 4 blocks, randomly assigns variety codes 1-49 in each block, fits # RCB model, computes mean squares for variety and residual. Repeat 40 times. # Kempton's estimate: variety = 1032, residual = 1013 # Our estimate: variety = 825, residual = 1080 fitfun <- function(dat){ dat <- transform(dat, block=factor(ceiling(row/7)), gen=factor(c(sample(1:49),sample(1:49),sample(1:49),sample(1:49)))) m2 <- lm(yield*100 ~ block + gen, dat) anova(m2)[2:3,'Mean Sq'] } set.seed(251) out <- replicate(50, fitfun(dat)) rowMeans(out) # 826 1079 } # }